Base | Representation |
---|---|
bin | 1001000110011011011110… |
… | …10011111010011011011111 |
3 | 2121212010210001121112221000 |
4 | 10203031233103322123133 |
5 | 10110334310222414403 |
6 | 110321235134241343 |
7 | 4133553664251513 |
oct | 443155723723337 |
9 | 77763701545830 |
10 | 20012120123103 |
11 | 64161021049a9 |
12 | 22b2596656253 |
13 | b2219a2b6504 |
14 | 4d283dbc8143 |
15 | 24a863e337a3 |
hex | 12336f4fa6df |
20012120123103 has 64 divisors (see below), whose sum is σ = 29976677406720. Its totient is φ = 13193780069376.
The previous prime is 20012120123089. The next prime is 20012120123113. The reversal of 20012120123103 is 30132102121002.
20012120123103 is a `hidden beast` number, since 200 + 121 + 20 + 12 + 310 + 3 = 666.
It is not a de Polignac number, because 20012120123103 - 28 = 20012120122847 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20012120123113) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5369496426 + ... + 5369500152.
It is an arithmetic number, because the mean of its divisors is an integer number (468385584480).
Almost surely, 220012120123103 is an apocalyptic number.
20012120123103 is a deficient number, since it is larger than the sum of its proper divisors (9964557283617).
20012120123103 is a wasteful number, since it uses less digits than its factorization.
20012120123103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6573 (or 6567 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 20012120123103 its reverse (30132102121002), we get a palindrome (50144222244105).
The spelling of 20012120123103 in words is "twenty trillion, twelve billion, one hundred twenty million, one hundred twenty-three thousand, one hundred three".
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