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200121219587713 is a prime number
BaseRepresentation
bin101101100000001001011010…
…001101001001111010000001
3222020120101211212200010220011
4231200021122031021322001
5202212241224203301323
61545342230305544521
760103165243646314
oct5540113215117201
9866511755603804
10200121219587713
1158845a293427a6
121a5409bb645141
138788472038288
14375bcc0d1897b
15182092b14e20d
hexb6025a349e81

200121219587713 has 2 divisors, whose sum is σ = 200121219587714. Its totient is φ = 200121219587712.

The previous prime is 200121219587701. The next prime is 200121219587749. The reversal of 200121219587713 is 317785912121002.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 186204910158864 + 13916309428849 = 13645692^2 + 3730457^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200121219587713 is a prime.

It is a super-3 number, since 3×2001212195877133 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (200121219587753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060609793856 + 100060609793857.

It is an arithmetic number, because the mean of its divisors is an integer number (100060609793857).

Almost surely, 2200121219587713 is an apocalyptic number.

It is an amenable number.

200121219587713 is a deficient number, since it is larger than the sum of its proper divisors (1).

200121219587713 is an equidigital number, since it uses as much as digits as its factorization.

200121219587713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 423360, while the sum is 49.

The spelling of 200121219587713 in words is "two hundred trillion, one hundred twenty-one billion, two hundred nineteen million, five hundred eighty-seven thousand, seven hundred thirteen".