Base | Representation |
---|---|
bin | 101101100000001001011010… |
… | …001111001001011010110001 |
3 | 222020120101211220122200100011 |
4 | 231200021122033021122301 |
5 | 202212241224322010001 |
6 | 1545342230325054521 |
7 | 60103165251253111 |
oct | 5540113217113261 |
9 | 866511756580304 |
10 | 200121220110001 |
11 | 58845a2966a143 |
12 | 1a5409bb857441 |
13 | 878847218bc18 |
14 | 375bcc1013041 |
15 | 182092b203d51 |
hex | b6025a3c96b1 |
200121220110001 has 2 divisors, whose sum is σ = 200121220110002. Its totient is φ = 200121220110000.
The previous prime is 200121220109957. The next prime is 200121220110043. The reversal of 200121220110001 is 100011022121002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128622273062976 + 71498947047025 = 11341176^2 + 8455705^2 .
It is a cyclic number.
It is not a de Polignac number, because 200121220110001 - 243 = 191325127087793 is a prime.
It is not a weakly prime, because it can be changed into another prime (200121220110061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060610055000 + 100060610055001.
It is an arithmetic number, because the mean of its divisors is an integer number (100060610055001).
Almost surely, 2200121220110001 is an apocalyptic number.
It is an amenable number.
200121220110001 is a deficient number, since it is larger than the sum of its proper divisors (1).
200121220110001 is an equidigital number, since it uses as much as digits as its factorization.
200121220110001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 200121220110001 its reverse (100011022121002), we get a palindrome (300132242231003).
The spelling of 200121220110001 in words is "two hundred trillion, one hundred twenty-one billion, two hundred twenty million, one hundred ten thousand, one".
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