Base | Representation |
---|---|
bin | 101101100000001001011010… |
… | …001111100010010100101011 |
3 | 222020120101211220211212021022 |
4 | 231200021122033202110223 |
5 | 202212241224333241021 |
6 | 1545342230331203055 |
7 | 60103165252156400 |
oct | 5540113217422453 |
9 | 866511756755238 |
10 | 200121220212011 |
11 | 58845a2972984a |
12 | 1a5409bb8a648b |
13 | 87884721c6497 |
14 | 375bcc103c2a7 |
15 | 182092b2241ab |
hex | b6025a3e252b |
200121220212011 has 6 divisors (see below), whose sum is σ = 232794072491580. Its totient is φ = 171532474467396.
The previous prime is 200121220211993. The next prime is 200121220212013. The reversal of 200121220212011 is 110212022121002.
It is not a de Polignac number, because 200121220212011 - 226 = 200121153103147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200121220212013) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2042053267421 + ... + 2042053267518.
It is an arithmetic number, because the mean of its divisors is an integer number (38799012081930).
Almost surely, 2200121220212011 is an apocalyptic number.
200121220212011 is a deficient number, since it is larger than the sum of its proper divisors (32672852279569).
200121220212011 is an equidigital number, since it uses as much as digits as its factorization.
200121220212011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4084106534953 (or 4084106534946 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 200121220212011 its reverse (110212022121002), we get a palindrome (310333242333013).
The spelling of 200121220212011 in words is "two hundred trillion, one hundred twenty-one billion, two hundred twenty million, two hundred twelve thousand, eleven".
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