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200122002120003 = 3591130632780339
BaseRepresentation
bin101101100000001010001000…
…110110010001110101000011
3222020120110212102010220101120
4231200022020312101311003
5202212244330020320003
61545342440102203323
760103223525241465
oct5540121066216503
9866513772126346
10200122002120003
11588462a00328a7
121a540b99723543
1387885681b3532
14375bd56c18135
151820974bc5853
hexb60288d91d43

200122002120003 has 8 divisors (see below), whose sum is σ = 271351867281600. Its totient is φ = 131153402519208.

The previous prime is 200122002119989. The next prime is 200122002120011. The reversal of 200122002120003 is 300021200221002.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 200122002120003 - 25 = 200122002119971 is a prime.

It is not an unprimeable number, because it can be changed into a prime (200122002120013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 565316389993 + ... + 565316390346.

It is an arithmetic number, because the mean of its divisors is an integer number (33918983410200).

Almost surely, 2200122002120003 is an apocalyptic number.

200122002120003 is a deficient number, since it is larger than the sum of its proper divisors (71229865161597).

200122002120003 is a wasteful number, since it uses less digits than its factorization.

200122002120003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1130632780401.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 200122002120003 its reverse (300021200221002), we get a palindrome (500143202341005).

The spelling of 200122002120003 in words is "two hundred trillion, one hundred twenty-two billion, two million, one hundred twenty thousand, three".

Divisors: 1 3 59 177 1130632780339 3391898341017 66707334040001 200122002120003