20012414113 has 2 divisors, whose sum is σ = 20012414114. Its totient is φ = 20012414112.

The previous prime is 20012414111. The next prime is 20012414137. The reversal of 20012414113 is 31141421002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10678535569 + 9333878544 = 103337^2 + 96612^2 .

It is a cyclic number.

It is not a de Polignac number, because 20012414113 - 2¹ = 20012414111 is a prime.

Together with 20012414111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (20012414111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006207056 + 10006207057.

It is an arithmetic number, because the mean of its divisors is an integer number (10006207057).

Almost surely, 2^20012414113 is an apocalyptic number.

It is an amenable number.

20012414113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20012414113 is an equidigital number, since it uses as much as digits as its factorization.

20012414113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 20012414113 its reverse (31141421002), we get a palindrome (51153835115).

The spelling of 20012414113 in words is "twenty billion, twelve million, four hundred fourteen thousand, one hundred thirteen".