Base | Representation |
---|---|
bin | 1011101001100001100… |
… | …1111001101011111111 |
3 | 201010120002021210121002 |
4 | 2322120121321223333 |
5 | 11234324102003320 |
6 | 231534130200515 |
7 | 20313203010536 |
oct | 2723031715377 |
9 | 633502253532 |
10 | 200125422335 |
11 | 77966646923 |
12 | 3295172313b |
13 | 15b442c4187 |
14 | 9986a0d31d |
15 | 531449b675 |
hex | 2e98679aff |
200125422335 has 32 divisors (see below), whose sum is σ = 261012326400. Its totient is φ = 146743159680.
The previous prime is 200125422313. The next prime is 200125422347. The reversal of 200125422335 is 533224521002.
It is not a de Polignac number, because 200125422335 - 210 = 200125421311 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200125422298 and 200125422307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16689212 + ... + 16701198.
It is an arithmetic number, because the mean of its divisors is an integer number (8156635200).
Almost surely, 2200125422335 is an apocalyptic number.
200125422335 is a deficient number, since it is larger than the sum of its proper divisors (60886904065).
200125422335 is a wasteful number, since it uses less digits than its factorization.
200125422335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17711.
The product of its (nonzero) digits is 14400, while the sum is 29.
Adding to 200125422335 its reverse (533224521002), we get a palindrome (733349943337).
The spelling of 200125422335 in words is "two hundred billion, one hundred twenty-five million, four hundred twenty-two thousand, three hundred thirty-five".
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