Base | Representation |
---|---|
bin | 11101000111110111010… |
… | …111110101001110001101 |
3 | 21002022201201212101000012 |
4 | 131013313113311032031 |
5 | 230242140330343201 |
6 | 4131220015043005 |
7 | 264406220265635 |
oct | 35076727651615 |
9 | 7068651771005 |
10 | 2001310012301 |
11 | 701829367486 |
12 | 283a4a810465 |
13 | 116951a96692 |
14 | 6cc148596c5 |
15 | 370d2ee95bb |
hex | 1d1f75f538d |
2001310012301 has 2 divisors, whose sum is σ = 2001310012302. Its totient is φ = 2001310012300.
The previous prime is 2001310012259. The next prime is 2001310012321. The reversal of 2001310012301 is 1032100131002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1458949936900 + 542360075401 = 1207870^2 + 736451^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2001310012301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001310012321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000655006150 + 1000655006151.
It is an arithmetic number, because the mean of its divisors is an integer number (1000655006151).
Almost surely, 22001310012301 is an apocalyptic number.
It is an amenable number.
2001310012301 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001310012301 is an equidigital number, since it uses as much as digits as its factorization.
2001310012301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 2001310012301 its reverse (1032100131002), we get a palindrome (3033410143303).
The spelling of 2001310012301 in words is "two trillion, one billion, three hundred ten million, twelve thousand, three hundred one".
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