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2001310013011 is a prime number
BaseRepresentation
bin11101000111110111010…
…111110101011001010011
321002022201201212101222111
4131013313113311121103
5230242140330404021
64131220015050151
7264406220301001
oct35076727653123
97068651771874
102001310013011
11701829367a71
12283a4a810957
13116951a96aba
146cc14859a71
15370d2ee98e1
hex1d1f75f5653

2001310013011 has 2 divisors, whose sum is σ = 2001310013012. Its totient is φ = 2001310013010.

The previous prime is 2001310012991. The next prime is 2001310013023. The reversal of 2001310013011 is 1103100131002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2001310013011 - 211 = 2001310010963 is a prime.

It is a super-2 number, since 2×20013100130112 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2001310012982 and 2001310013000.

It is not a weakly prime, because it can be changed into another prime (2001310013041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000655006505 + 1000655006506.

It is an arithmetic number, because the mean of its divisors is an integer number (1000655006506).

Almost surely, 22001310013011 is an apocalyptic number.

2001310013011 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001310013011 is an equidigital number, since it uses as much as digits as its factorization.

2001310013011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 2001310013011 its reverse (1103100131002), we get a palindrome (3104410144013).

The spelling of 2001310013011 in words is "two trillion, one billion, three hundred ten million, thirteen thousand, eleven".