Base | Representation |
---|---|
bin | 11101000111110111011… |
… | …001000010110010110111 |
3 | 21002022201202110111212021 |
4 | 131013313121002302313 |
5 | 230242140421030124 |
6 | 4131220025534011 |
7 | 264406223061166 |
oct | 35076731026267 |
9 | 7068652414767 |
10 | 2001310330039 |
11 | 701829564179 |
12 | 283a4a944307 |
13 | 116951b781a7 |
14 | 6cc148dd3dd |
15 | 370d305d7e4 |
hex | 1d1f7642cb7 |
2001310330039 has 2 divisors, whose sum is σ = 2001310330040. Its totient is φ = 2001310330038.
The previous prime is 2001310330009. The next prime is 2001310330043. The reversal of 2001310330039 is 9300330131002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2001310330039 - 213 = 2001310321847 is a prime.
It is a super-2 number, since 2×20013103300392 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2001310329995 and 2001310330022.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001310330009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000655165019 + 1000655165020.
It is an arithmetic number, because the mean of its divisors is an integer number (1000655165020).
Almost surely, 22001310330039 is an apocalyptic number.
2001310330039 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001310330039 is an equidigital number, since it uses as much as digits as its factorization.
2001310330039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 25.
The spelling of 2001310330039 in words is "two trillion, one billion, three hundred ten million, three hundred thirty thousand, thirty-nine".
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