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200131114411 = 456743821133
BaseRepresentation
bin1011101001100010111…
…1100111010110101011
3201010120110222222122201
42322120233213112223
511234332031130121
6231534452201031
720313302255524
oct2723057472653
9633513888581
10200131114411
1177969884418
1232953609177
1315b45537c77
14998769184b
155314c22e91
hex2e98be75ab

200131114411 has 4 divisors (see below), whose sum is σ = 200174940112. Its totient is φ = 200087288712.

The previous prime is 200131114363. The next prime is 200131114427. The reversal of 200131114411 is 114411131002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200131114411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200131114471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21906000 + ... + 21915133.

It is an arithmetic number, because the mean of its divisors is an integer number (50043735028).

Almost surely, 2200131114411 is an apocalyptic number.

200131114411 is a deficient number, since it is larger than the sum of its proper divisors (43825701).

200131114411 is an equidigital number, since it uses as much as digits as its factorization.

200131114411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43825700.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 200131114411 its reverse (114411131002), we get a palindrome (314542245413).

The spelling of 200131114411 in words is "two hundred billion, one hundred thirty-one million, one hundred fourteen thousand, four hundred eleven".

Divisors: 1 4567 43821133 200131114411