Base | Representation |
---|---|
bin | 1001000110011101010101… |
… | …00011101101110101010011 |
3 | 2121212020100022222220110111 |
4 | 10203032222203231311103 |
5 | 10110343324203342210 |
6 | 110321521523142151 |
7 | 4133620424145262 |
oct | 443165243556523 |
9 | 77766308886414 |
10 | 20013114121555 |
11 | 64165721a9725 |
12 | 22b2813514957 |
13 | b222c8201a89 |
14 | 4d28d5c125d9 |
15 | 24a8c132b88a |
hex | 1233aa8edd53 |
20013114121555 has 8 divisors (see below), whose sum is σ = 24020374114800. Its totient is φ = 16007399851296.
The previous prime is 20013114121543. The next prime is 20013114121571. The reversal of 20013114121555 is 55512141131002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 20013114121555 - 25 = 20013114121523 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 386402260 + ... + 386454049.
It is an arithmetic number, because the mean of its divisors is an integer number (3002546764350).
Almost surely, 220013114121555 is an apocalyptic number.
20013114121555 is a deficient number, since it is larger than the sum of its proper divisors (4007259993245).
20013114121555 is an equidigital number, since it uses as much as digits as its factorization.
20013114121555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 772861493.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 20013114121555 its reverse (55512141131002), we get a palindrome (75525255252557).
The spelling of 20013114121555 in words is "twenty trillion, thirteen billion, one hundred fourteen million, one hundred twenty-one thousand, five hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •