Base | Representation |
---|---|
bin | 101101100000010100011111… |
… | …100101100110010000100000 |
3 | 222020121112120022100122011122 |
4 | 231200110133211212100200 |
5 | 202212440112441311230 |
6 | 1545351515255231412 |
7 | 60104066210434166 |
oct | 5540243745462040 |
9 | 866545508318148 |
10 | 200133121041440 |
11 | 5884aa86406074 |
12 | 1a543181378568 |
13 | 878961a947ba2 |
14 | 375c6cd803236 |
15 | 1820dc5e05be5 |
hex | b6051f966420 |
200133121041440 has 192 divisors, whose sum is σ = 503937961712640. Its totient is φ = 74933197701120.
The previous prime is 200133121041391. The next prime is 200133121041449. The reversal of 200133121041440 is 44140121331002.
It is a super-2 number, since 2×2001331210414402 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (200133121041449) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1326354800 + ... + 1326505680.
It is an arithmetic number, because the mean of its divisors is an integer number (2624676883920).
Almost surely, 2200133121041440 is an apocalyptic number.
200133121041440 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 200133121041440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (251968980856320).
200133121041440 is an abundant number, since it is smaller than the sum of its proper divisors (303804840671200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200133121041440 is a wasteful number, since it uses less digits than its factorization.
200133121041440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158635 (or 158627 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 200133121041440 its reverse (44140121331002), we get a palindrome (244273242372442).
The spelling of 200133121041440 in words is "two hundred trillion, one hundred thirty-three billion, one hundred twenty-one million, forty-one thousand, four hundred forty".
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