20013555433 has 2 divisors, whose sum is σ = 20013555434. Its totient is φ = 20013555432.

The previous prime is 20013555431. The next prime is 20013555449. The reversal of 20013555433 is 33455531002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18482946304 + 1530609129 = 135952^2 + 39123^2 .

It is a cyclic number.

It is not a de Polignac number, because 20013555433 - 2¹ = 20013555431 is a prime.

Together with 20013555431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 20013555395 and 20013555404.

It is not a weakly prime, because it can be changed into another prime (20013555431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006777716 + 10006777717.

It is an arithmetic number, because the mean of its divisors is an integer number (10006777717).

Almost surely, 2^20013555433 is an apocalyptic number.

It is an amenable number.

20013555433 is a deficient number, since it is larger than the sum of its proper divisors (1).

20013555433 is an equidigital number, since it uses as much as digits as its factorization.

20013555433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27000, while the sum is 31.

The spelling of 20013555433 in words is "twenty billion, thirteen million, five hundred fifty-five thousand, four hundred thirty-three".