Base | Representation |
---|---|
bin | 10010101000111011… |
… | …011100010101000001 |
3 | 1220122210220202120012 |
4 | 102220323130111001 |
5 | 311442042232001 |
6 | 13105545554305 |
7 | 1305652253126 |
oct | 225073342501 |
9 | 56583822505 |
10 | 20014024001 |
11 | 8540438504 |
12 | 3a667a5995 |
13 | 1b6c577c6a |
14 | d7c0d674d |
15 | 7c20db2bb |
hex | 4a8edc541 |
20014024001 has 2 divisors, whose sum is σ = 20014024002. Its totient is φ = 20014024000.
The previous prime is 20014023961. The next prime is 20014024003. The reversal of 20014024001 is 10042041002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10197970225 + 9816053776 = 100985^2 + 99076^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20014024001 is a prime.
It is a super-2 number, since 2×200140240012 (a number of 21 digits) contains 22 as substring.
Together with 20014024003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20014024003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10007012000 + 10007012001.
It is an arithmetic number, because the mean of its divisors is an integer number (10007012001).
Almost surely, 220014024001 is an apocalyptic number.
It is an amenable number.
20014024001 is a deficient number, since it is larger than the sum of its proper divisors (1).
20014024001 is an equidigital number, since it uses as much as digits as its factorization.
20014024001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 14.
Adding to 20014024001 its reverse (10042041002), we get a palindrome (30056065003).
The spelling of 20014024001 in words is "twenty billion, fourteen million, twenty-four thousand, one".
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