200141244131 has 2 divisors, whose sum is σ = 200141244132. Its totient is φ = 200141244130.

The previous prime is 200141244113. The next prime is 200141244169. The reversal of 200141244131 is 131442141002.

200141244131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (200141244113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-200141244131 is a prime.

It is a super-2 number, since 2×200141244131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 200141244097 and 200141244106.

It is not a weakly prime, because it can be changed into another prime (200141244101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100070622065 + 100070622066.

It is an arithmetic number, because the mean of its divisors is an integer number (100070622066).

Almost surely, 2^200141244131 is an apocalyptic number.

200141244131 is a deficient number, since it is larger than the sum of its proper divisors (1).

200141244131 is an equidigital number, since it uses as much as digits as its factorization.

200141244131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 200141244131 its reverse (131442141002), we get a palindrome (331583385133).

The spelling of 200141244131 in words is "two hundred billion, one hundred forty-one million, two hundred forty-four thousand, one hundred thirty-one".