Base | Representation |
---|---|
bin | 1011101001100101100… |
… | …1001001101111001111 |
3 | 201010121020111012012101 |
4 | 2322121121021233033 |
5 | 11234342323100101 |
6 | 231535521415531 |
7 | 20313463646236 |
oct | 2723131115717 |
9 | 633536435171 |
10 | 200142003151 |
11 | 77974a41282 |
12 | 3295719a5a7 |
13 | 15b4787b1cc |
14 | 9988cc7b1d |
15 | 5315b74401 |
hex | 2e99649bcf |
200142003151 has 2 divisors, whose sum is σ = 200142003152. Its totient is φ = 200142003150.
The previous prime is 200142003059. The next prime is 200142003169. The reversal of 200142003151 is 151300241002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200142003151 - 223 = 200133614543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200142007151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100071001575 + 100071001576.
It is an arithmetic number, because the mean of its divisors is an integer number (100071001576).
Almost surely, 2200142003151 is an apocalyptic number.
200142003151 is a deficient number, since it is larger than the sum of its proper divisors (1).
200142003151 is an equidigital number, since it uses as much as digits as its factorization.
200142003151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 19.
Adding to 200142003151 its reverse (151300241002), we get a palindrome (351442244153).
The spelling of 200142003151 in words is "two hundred billion, one hundred forty-two million, three thousand, one hundred fifty-one".
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