Base | Representation |
---|---|
bin | 101101100000011101001010… |
… | …101111100101010111011111 |
3 | 222020122102121102020110201102 |
4 | 231200131022233211113133 |
5 | 202213113201330422421 |
6 | 1545400055414103315 |
7 | 60104546055051362 |
oct | 5540351257452737 |
9 | 866572542213642 |
10 | 200142435014111 |
11 | 58853a25954647 |
12 | 1a544b4064ab3b |
13 | 878a473478b15 |
14 | 375cd347c80d9 |
15 | 182126d95160b |
hex | b6074abe55df |
200142435014111 has 2 divisors, whose sum is σ = 200142435014112. Its totient is φ = 200142435014110.
The previous prime is 200142435014107. The next prime is 200142435014153. The reversal of 200142435014111 is 111410534241002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200142435014111 - 22 = 200142435014107 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200142435014101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100071217507055 + 100071217507056.
It is an arithmetic number, because the mean of its divisors is an integer number (100071217507056).
Almost surely, 2200142435014111 is an apocalyptic number.
200142435014111 is a deficient number, since it is larger than the sum of its proper divisors (1).
200142435014111 is an equidigital number, since it uses as much as digits as its factorization.
200142435014111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 29.
Adding to 200142435014111 its reverse (111410534241002), we get a palindrome (311552969255113).
The spelling of 200142435014111 in words is "two hundred trillion, one hundred forty-two billion, four hundred thirty-five million, fourteen thousand, one hundred eleven".
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