200143101432013 has 8 divisors (see below), whose sum is σ = 200167879168832. Its totient is φ = 200118324309696.

The previous prime is 200143101431993. The next prime is 200143101432017. The reversal of 200143101432013 is 310234101341002.

200143101432013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 200143101432013 - 2¹⁷ = 200143101300941 is a prime.

It is a super-4 number, since 4×200143101432013⁴ (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200143101432017) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1238988256 + ... + 1239149782.

It is an arithmetic number, because the mean of its divisors is an integer number (25020984896104).

Almost surely, 2^{200143101432013} is an apocalyptic number.

It is an amenable number.

200143101432013 is a deficient number, since it is larger than the sum of its proper divisors (24777736819).

200143101432013 is a wasteful number, since it uses less digits than its factorization.

200143101432013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 307251.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 200143101432013 its reverse (310234101341002), we get a palindrome (510377202773015).

The spelling of 200143101432013 in words is "two hundred trillion, one hundred forty-three billion, one hundred one million, four hundred thirty-two thousand, thirteen".