Base | Representation |
---|---|
bin | 1001000110011111100011… |
… | …11010010000010110011100 |
3 | 2121212100102202112102110002 |
4 | 10203033301322100112130 |
5 | 10110403302132244234 |
6 | 110322240405033432 |
7 | 4133662201226213 |
oct | 443176172202634 |
9 | 77770382472402 |
10 | 20014311212444 |
11 | 64170269a883a |
12 | 22b2aa83b5878 |
13 | b22459218093 |
14 | 4d29aabc607a |
15 | 24a94149027e |
hex | 1233f1e9059c |
20014311212444 has 12 divisors (see below), whose sum is σ = 35447033111784. Its totient is φ = 9886587466224.
The previous prime is 20014311212443. The next prime is 20014311212449. The reversal of 20014311212444 is 44421211341002.
20014311212444 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20014311212443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30142034627 + ... + 30142035290.
It is an arithmetic number, because the mean of its divisors is an integer number (2953919425982).
Almost surely, 220014311212444 is an apocalyptic number.
It is an amenable number.
20014311212444 is a deficient number, since it is larger than the sum of its proper divisors (15432721899340).
20014311212444 is a wasteful number, since it uses less digits than its factorization.
20014311212444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60284070004 (or 60284070002 counting only the distinct ones).
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 20014311212444 its reverse (44421211341002), we get a palindrome (64435522553446).
The spelling of 20014311212444 in words is "twenty trillion, fourteen billion, three hundred eleven million, two hundred twelve thousand, four hundred forty-four".
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