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200143552141 = 1337483186131
BaseRepresentation
bin1011101001100101111…
…1000011111010001101
3201010121100101220000101
42322121133003322031
511234343222132031
6231540014531101
720313513060241
oct2723137037215
9633540356011
10200143552141
11779758aa035
1232957806a91
1315b47ca1280
1499891ac421
155315d7d361
hex2e997c3e8d

200143552141 has 16 divisors (see below), whose sum is σ = 221412986368. Its totient is φ = 179715412800.

The previous prime is 200143552123. The next prime is 200143552151. The reversal of 200143552141 is 141255341002.

It is a cyclic number.

It is not a de Polignac number, because 200143552141 - 213 = 200143543949 is a prime.

It is a super-4 number, since 4×2001435521414 (a number of 46 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200143552121) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2280646 + ... + 2366776.

It is an arithmetic number, because the mean of its divisors is an integer number (13838311648).

Almost surely, 2200143552141 is an apocalyptic number.

It is an amenable number.

200143552141 is a deficient number, since it is larger than the sum of its proper divisors (21269434227).

200143552141 is a wasteful number, since it uses less digits than its factorization.

200143552141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91012.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 200143552141 its reverse (141255341002), we get a palindrome (341398893143).

The spelling of 200143552141 in words is "two hundred billion, one hundred forty-three million, five hundred fifty-two thousand, one hundred forty-one".

Divisors: 1 13 37 481 4831 62803 86131 178747 1119703 2323711 3186847 41429011 416098861 5409285193 15395657857 200143552141