2001442113133 has 4 divisors (see below), whose sum is σ = 2002317254080. Its totient is φ = 2000566972188.

The previous prime is 2001442113067. The next prime is 2001442113163. The reversal of 2001442113133 is 3313112441002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2001442113133 - 2²⁹ = 2000905242221 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2001442113098 and 2001442113107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2001442113163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 437567043 + ... + 437571616.

It is an arithmetic number, because the mean of its divisors is an integer number (500579313520).

Almost surely, 2^{2001442113133} is an apocalyptic number.

It is an amenable number.

2001442113133 is a deficient number, since it is larger than the sum of its proper divisors (875140947).

2001442113133 is an equidigital number, since it uses as much as digits as its factorization.

2001442113133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 875140946.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 2001442113133 its reverse (3313112441002), we get a palindrome (5314554554135).

The spelling of 2001442113133 in words is "two trillion, one billion, four hundred forty-two million, one hundred thirteen thousand, one hundred thirty-three".