Base | Representation |
---|---|
bin | 11101000111111111011… |
… | …000001001000110000111 |
3 | 21002100002002120110210001 |
4 | 131013333120021012013 |
5 | 230242424220431211 |
6 | 4131241213342131 |
7 | 264412440643405 |
oct | 35077730110607 |
9 | 7070062513701 |
10 | 2001444311431 |
11 | 7018981553a4 |
12 | 283a87797947 |
13 | 116973858c16 |
14 | 6cc28618475 |
15 | 370debc6ac1 |
hex | 1d1ff609187 |
2001444311431 has 2 divisors, whose sum is σ = 2001444311432. Its totient is φ = 2001444311430.
The previous prime is 2001444311387. The next prime is 2001444311441. The reversal of 2001444311431 is 1341134441002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2001444311431 is a prime.
It is a super-2 number, since 2×20014443114312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2001444311431.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001444311441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000722155715 + 1000722155716.
It is an arithmetic number, because the mean of its divisors is an integer number (1000722155716).
Almost surely, 22001444311431 is an apocalyptic number.
2001444311431 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001444311431 is an equidigital number, since it uses as much as digits as its factorization.
2001444311431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 2001444311431 its reverse (1341134441002), we get a palindrome (3342578752433).
The spelling of 2001444311431 in words is "two trillion, one billion, four hundred forty-four million, three hundred eleven thousand, four hundred thirty-one".
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