Base | Representation |
---|---|
bin | 1001000110011111110100… |
… | …01111100111110010000011 |
3 | 2121212100210111121221200110 |
4 | 10203033322033213302003 |
5 | 10110404043430444141 |
6 | 110322302321522403 |
7 | 4133665516533042 |
oct | 443177217476203 |
9 | 77770714557613 |
10 | 20014451031171 |
11 | 6417098916703 |
12 | 22b2b271a3403 |
13 | b2247c190a5c |
14 | 4d29c15c0559 |
15 | 24a94d8ace16 |
hex | 1233fa3e7c83 |
20014451031171 has 4 divisors (see below), whose sum is σ = 26685934708232. Its totient is φ = 13342967354112.
The previous prime is 20014451031167. The next prime is 20014451031199. The reversal of 20014451031171 is 17113015441002.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 20014451031171 - 22 = 20014451031167 is a prime.
It is a super-3 number, since 3×200144510311713 (a number of 41 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20014451031131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3335741838526 + ... + 3335741838531.
It is an arithmetic number, because the mean of its divisors is an integer number (6671483677058).
Almost surely, 220014451031171 is an apocalyptic number.
20014451031171 is a deficient number, since it is larger than the sum of its proper divisors (6671483677061).
20014451031171 is an equidigital number, since it uses as much as digits as its factorization.
20014451031171 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6671483677060.
The product of its (nonzero) digits is 3360, while the sum is 30.
Adding to 20014451031171 its reverse (17113015441002), we get a palindrome (37127466472173).
The spelling of 20014451031171 in words is "twenty trillion, fourteen billion, four hundred fifty-one million, thirty-one thousand, one hundred seventy-one".
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