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20015417481 = 36671805827
BaseRepresentation
bin10010101001000000…
…110000100010001001
31220122220112120001120
4102221000300202021
5311442421324411
613110035505453
71306000145553
oct225100604211
956586476046
1020015417481
1185411aa444
123a67158289
131b6c9452c7
14d7c37a4d3
157c22b4106
hex4a9030889

20015417481 has 4 divisors (see below), whose sum is σ = 26687223312. Its totient is φ = 13343611652.

The previous prime is 20015417467. The next prime is 20015417491. The reversal of 20015417481 is 18471451002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20015417481 - 215 = 20015384713 is a prime.

It is a super-2 number, since 2×200154174812 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (20015417491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3335902911 + ... + 3335902916.

It is an arithmetic number, because the mean of its divisors is an integer number (6671805828).

Almost surely, 220015417481 is an apocalyptic number.

It is an amenable number.

20015417481 is a deficient number, since it is larger than the sum of its proper divisors (6671805831).

20015417481 is an equidigital number, since it uses as much as digits as its factorization.

20015417481 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6671805830.

The product of its (nonzero) digits is 8960, while the sum is 33.

Adding to 20015417481 its reverse (18471451002), we get a palindrome (38486868483).

The spelling of 20015417481 in words is "twenty billion, fifteen million, four hundred seventeen thousand, four hundred eighty-one".

Divisors: 1 3 6671805827 20015417481