200204113 has 2 divisors, whose sum is σ = 200204114. Its totient is φ = 200204112.

The previous prime is 200204047. The next prime is 200204129. The reversal of 200204113 is 311402002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 199600384 + 603729 = 14128^2 + 777^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-200204113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200204093 and 200204102.

It is not a weakly prime, because it can be changed into another prime (200204413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100102056 + 100102057.

It is an arithmetic number, because the mean of its divisors is an integer number (100102057).

Almost surely, 2^200204113 is an apocalyptic number.

It is an amenable number.

200204113 is a deficient number, since it is larger than the sum of its proper divisors (1).

200204113 is an equidigital number, since it uses as much as digits as its factorization.

200204113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 200204113 is about 14149.3502677685. The cubic root of 200204113 is about 585.0024233469.

Adding to 200204113 its reverse (311402002), we get a palindrome (511606115).

The spelling of 200204113 in words is "two hundred million, two hundred four thousand, one hundred thirteen".