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200204420424131 = 414883034644491
BaseRepresentation
bin101101100001010110111001…
…010111001010000111000011
3222020212100121021201120000002
4231201112321113022013003
5202220122123112033011
61545444350244350215
760112202113253444
oct5541267127120703
9866770537646002
10200204420424131
1158878244013632
121a554b5b3a536b
138793271342526
143761d34c192cb
151822b9a633c3b
hexb615b95ca1c3

200204420424131 has 4 divisors (see below), whose sum is σ = 205087455068664. Its totient is φ = 195321385779600.

The previous prime is 200204420424103. The next prime is 200204420424199. The reversal of 200204420424131 is 131424024402002.

It is a happy number.

200204420424131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200204420424131 - 234 = 200187240554947 is a prime.

It is a super-2 number, since 2×2002044204241312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200204420424094 and 200204420424103.

It is not an unprimeable number, because it can be changed into a prime (200204420424331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2441517322205 + ... + 2441517322286.

It is an arithmetic number, because the mean of its divisors is an integer number (51271863767166).

Almost surely, 2200204420424131 is an apocalyptic number.

200204420424131 is a deficient number, since it is larger than the sum of its proper divisors (4883034644533).

200204420424131 is an equidigital number, since it uses as much as digits as its factorization.

200204420424131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4883034644532.

The product of its (nonzero) digits is 12288, while the sum is 29.

Adding to 200204420424131 its reverse (131424024402002), we get a palindrome (331628444826133).

The spelling of 200204420424131 in words is "two hundred trillion, two hundred four billion, four hundred twenty million, four hundred twenty-four thousand, one hundred thirty-one".

Divisors: 1 41 4883034644491 200204420424131