Base | Representation |
---|---|
bin | 101101100001010111011110… |
… | …011011111011011000111001 |
3 | 222020212102012122010210202201 |
4 | 231201113132123323120321 |
5 | 202220124411330302140 |
6 | 1545444532104230201 |
7 | 60112223405242234 |
oct | 5541273633733071 |
9 | 866772178123681 |
10 | 200205042431545 |
11 | 58878533132a48 |
12 | 1a5550b376b361 |
13 | 8793340175158 |
14 | 3761d9369041b |
15 | 1822bd504c49a |
hex | b615de6fb639 |
200205042431545 has 4 divisors (see below), whose sum is σ = 240246050917860. Its totient is φ = 160164033945232.
The previous prime is 200205042431531. The next prime is 200205042431683. The reversal of 200205042431545 is 545134240502002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 80028482706496 + 120176559725049 = 8945864^2 + 10962507^2 .
It is a cyclic number.
It is not a de Polignac number, because 200205042431545 - 221 = 200205040334393 is a prime.
It is a super-3 number, since 3×2002050424315453 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20020504243150 + ... + 20020504243159.
It is an arithmetic number, because the mean of its divisors is an integer number (60061512729465).
Almost surely, 2200205042431545 is an apocalyptic number.
It is an amenable number.
200205042431545 is a deficient number, since it is larger than the sum of its proper divisors (40041008486315).
200205042431545 is an equidigital number, since it uses as much as digits as its factorization.
200205042431545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40041008486314.
The product of its (nonzero) digits is 192000, while the sum is 37.
Adding to 200205042431545 its reverse (545134240502002), we get a palindrome (745339282933547).
The spelling of 200205042431545 in words is "two hundred trillion, two hundred five billion, forty-two million, four hundred thirty-one thousand, five hundred forty-five".
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