Base | Representation |
---|---|
bin | 101101100001011100001100… |
… | …000001000100111111110111 |
3 | 222020212220021020211012212021 |
4 | 231201130030001010333313 |
5 | 202220220242120042442 |
6 | 1545451130130534011 |
7 | 60112462653644023 |
oct | 5541341401047767 |
9 | 866786236735767 |
10 | 200210102112247 |
11 | 5887a69a1a2a47 |
12 | 1a556086137307 |
13 | 879396849b566 |
14 | 3762313649383 |
15 | 1822dce341e67 |
hex | b6170c044ff7 |
200210102112247 has 2 divisors, whose sum is σ = 200210102112248. Its totient is φ = 200210102112246.
The previous prime is 200210102112217. The next prime is 200210102112253. The reversal of 200210102112247 is 742211201012002.
200210102112247 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200210102112247 - 243 = 191414009090039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200210102112217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105051056123 + 100105051056124.
It is an arithmetic number, because the mean of its divisors is an integer number (100105051056124).
Almost surely, 2200210102112247 is an apocalyptic number.
200210102112247 is a deficient number, since it is larger than the sum of its proper divisors (1).
200210102112247 is an equidigital number, since it uses as much as digits as its factorization.
200210102112247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 200210102112247 its reverse (742211201012002), we get a palindrome (942421303124249).
The spelling of 200210102112247 in words is "two hundred trillion, two hundred ten billion, one hundred two million, one hundred twelve thousand, two hundred forty-seven".
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