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2002101103 = 5933933917
BaseRepresentation
bin111011101010101…
…1010001101101111
312011112022021101201
41313111122031233
513100014213403
6530355550331
7100420402312
oct16725321557
95145267351
102002101103
11938152212
1247a5bb3a7
1325ba31812
1414dc84979
15bab7a21d
hex7755a36f

2002101103 has 4 divisors (see below), whose sum is σ = 2036035080. Its totient is φ = 1968167128.

The previous prime is 2002101091. The next prime is 2002101107. The reversal of 2002101103 is 3011012002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2002101103 - 25 = 2002101071 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2002101103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002101107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16966900 + ... + 16967017.

It is an arithmetic number, because the mean of its divisors is an integer number (509008770).

Almost surely, 22002101103 is an apocalyptic number.

2002101103 is a deficient number, since it is larger than the sum of its proper divisors (33933977).

2002101103 is an equidigital number, since it uses as much as digits as its factorization.

2002101103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33933976.

The product of its (nonzero) digits is 12, while the sum is 10.

The square root of 2002101103 is about 44744.8444292748. The cubic root of 2002101103 is about 1260.3620994654.

Adding to 2002101103 its reverse (3011012002), we get a palindrome (5013113105).

The spelling of 2002101103 in words is "two billion, two million, one hundred one thousand, one hundred three".

Divisors: 1 59 33933917 2002101103