Base | Representation |
---|---|
bin | 11101001000100110100… |
… | …001111110100101100011 |
3 | 21002101202212121221012122 |
4 | 131020212201332211203 |
5 | 230300300401420001 |
6 | 4131430321014455 |
7 | 264434635264154 |
oct | 35104641764543 |
9 | 7071685557178 |
10 | 2002101201251 |
11 | 7020a4a2a448 |
12 | 28402b78442b |
13 | 116a49982c18 |
14 | 6cc8b96d92b |
15 | 3712c6d0b1b |
hex | 1d22687e963 |
2002101201251 has 2 divisors, whose sum is σ = 2002101201252. Its totient is φ = 2002101201250.
The previous prime is 2002101201209. The next prime is 2002101201263. The reversal of 2002101201251 is 1521021012002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2002101201251 - 210 = 2002101200227 is a prime.
It is not a weakly prime, because it can be changed into another prime (2002101200251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001050600625 + 1001050600626.
It is an arithmetic number, because the mean of its divisors is an integer number (1001050600626).
Almost surely, 22002101201251 is an apocalyptic number.
2002101201251 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002101201251 is an equidigital number, since it uses as much as digits as its factorization.
2002101201251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 2002101201251 its reverse (1521021012002), we get a palindrome (3523122213253).
The spelling of 2002101201251 in words is "two trillion, two billion, one hundred one million, two hundred one thousand, two hundred fifty-one".
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