20021100000113 has 2 divisors, whose sum is σ = 20021100000114. Its totient is φ = 20021100000112.

The previous prime is 20021100000049. The next prime is 20021100000131. The reversal of 20021100000113 is 31100000112002.

Together with next prime (20021100000131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19332843929569 + 688256070544 = 4396913^2 + 829612^2 .

It is a cyclic number.

It is not a de Polignac number, because 20021100000113 - 2⁶ = 20021100000049 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 20021100000094 and 20021100000103.

It is not a weakly prime, because it can be changed into another prime (20021100000163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010550000056 + 10010550000057.

It is an arithmetic number, because the mean of its divisors is an integer number (10010550000057).

Almost surely, 2^{20021100000113} is an apocalyptic number.

It is an amenable number.

20021100000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20021100000113 is an equidigital number, since it uses as much as digits as its factorization.

20021100000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 20021100000113 its reverse (31100000112002), we get a palindrome (51121100112115).

The spelling of 20021100000113 in words is "twenty trillion, twenty-one billion, one hundred million, one hundred thirteen", and thus it is an aban number.