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200211001999973 is a prime number
BaseRepresentation
bin101101100001011101000001…
…101001111000001001100101
3222020212222120222010020202022
4231201131001221320021211
5202220224113002444343
61545451355314352525
760112524161604266
oct5541350151701145
9866788528106668
10200211001999973
1158880011158a08
121a55629758b745
138793a7ca55ac3
14376239ad7696d
151822e3334a568
hexb61741a78265

200211001999973 has 2 divisors, whose sum is σ = 200211001999974. Its totient is φ = 200211001999972.

The previous prime is 200211001999919. The next prime is 200211002000003. The reversal of 200211001999973 is 379999100112002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138067153039204 + 62143848960769 = 11750198^2 + 7883137^2 .

It is a cyclic number.

It is not a de Polignac number, because 200211001999973 - 212 = 200211001995877 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200211001992973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105500999986 + 100105500999987.

It is an arithmetic number, because the mean of its divisors is an integer number (100105500999987).

Almost surely, 2200211001999973 is an apocalyptic number.

It is an amenable number.

200211001999973 is a deficient number, since it is larger than the sum of its proper divisors (1).

200211001999973 is an equidigital number, since it uses as much as digits as its factorization.

200211001999973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 551124, while the sum is 53.

The spelling of 200211001999973 in words is "two hundred trillion, two hundred eleven billion, one million, nine hundred ninety-nine thousand, nine hundred seventy-three".