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2002110030113 = 5933934068307
BaseRepresentation
bin11101001000100111000…
…011101010000100100001
321002101210111020111010112
4131020213003222010201
5230300310131430423
64131431234141105
7264435103315244
oct35104703520441
97071714214115
102002110030113
117020a9a0a726
12284032721795
13116a4b7546bb
146cc8cbcb25b
153712d376a78
hex1d2270ea121

2002110030113 has 4 divisors (see below), whose sum is σ = 2036044098480. Its totient is φ = 1968175961748.

The previous prime is 2002110030091. The next prime is 2002110030119. The reversal of 2002110030113 is 3110300112002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002110030113 - 224 = 2002093252897 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002110030119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16967034095 + ... + 16967034212.

It is an arithmetic number, because the mean of its divisors is an integer number (509011024620).

Almost surely, 22002110030113 is an apocalyptic number.

It is an amenable number.

2002110030113 is a deficient number, since it is larger than the sum of its proper divisors (33934068367).

2002110030113 is an equidigital number, since it uses as much as digits as its factorization.

2002110030113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33934068366.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 2002110030113 its reverse (3110300112002), we get a palindrome (5112410142115).

The spelling of 2002110030113 in words is "two trillion, two billion, one hundred ten million, thirty thousand, one hundred thirteen".

Divisors: 1 59 33934068307 2002110030113