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200211033312121 = 1331349203989509
BaseRepresentation
bin101101100001011101000011…
…100001010100101101111001
3222020212222200011001001221111
4231201131003201110231321
5202220224144011441441
61545451402353440321
760112525022006326
oct5541350341245571
9866788604031844
10200211033312121
11588800278a5217
121a5562a5b700a1
138793a8639a0c0
1437623a11a7b4d
151822e35e83081
hexb61743854b79

200211033312121 has 8 divisors (see below), whose sum is σ = 216300737885960. Its totient is φ = 184219736717952.

The previous prime is 200211033312079. The next prime is 200211033312167. The reversal of 200211033312121 is 121213330112002.

200211033312121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 33228710869225 + 166982322442896 = 5764435^2 + 12922164^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 200211033312121 - 229 = 200210496441209 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200211033312092 and 200211033312101.

It is not an unprimeable number, because it can be changed into a prime (200211033312821) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24601990686 + ... + 24601998823.

It is an arithmetic number, because the mean of its divisors is an integer number (27037592235745).

Almost surely, 2200211033312121 is an apocalyptic number.

It is an amenable number.

200211033312121 is a deficient number, since it is larger than the sum of its proper divisors (16089704573839).

200211033312121 is a wasteful number, since it uses less digits than its factorization.

200211033312121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49203989835.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 200211033312121 its reverse (121213330112002), we get a palindrome (321424363424123).

The spelling of 200211033312121 in words is "two hundred trillion, two hundred eleven billion, thirty-three million, three hundred twelve thousand, one hundred twenty-one".

Divisors: 1 13 313 4069 49203989509 639651863617 15400848716317 200211033312121