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20021113127 is a prime number
BaseRepresentation
bin10010101001010110…
…011111000100100111
31220200022020221000102
4102221112133010213
5312000401110002
613110401534315
71306066440131
oct225126370447
956608227012
1020021113127
11854443a694
123a6904439b
131b70b8a902
14d7d020051
157c2a3ba02
hex4a959f127

20021113127 has 2 divisors, whose sum is σ = 20021113128. Its totient is φ = 20021113126.

The previous prime is 20021113097. The next prime is 20021113207. The reversal of 20021113127 is 72131112002.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20021113127 - 210 = 20021112103 is a prime.

It is a super-5 number, since 5×200211131275 (a number of 53 digits) contains 55555 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20021113099 and 20021113108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20021103127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010556563 + 10010556564.

It is an arithmetic number, because the mean of its divisors is an integer number (10010556564).

Almost surely, 220021113127 is an apocalyptic number.

20021113127 is a deficient number, since it is larger than the sum of its proper divisors (1).

20021113127 is an equidigital number, since it uses as much as digits as its factorization.

20021113127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 20.

Adding to 20021113127 its reverse (72131112002), we get a palindrome (92152225129).

The spelling of 20021113127 in words is "twenty billion, twenty-one million, one hundred thirteen thousand, one hundred twenty-seven".