Base | Representation |
---|---|
bin | 10010101001010110… |
… | …011111000100100111 |
3 | 1220200022020221000102 |
4 | 102221112133010213 |
5 | 312000401110002 |
6 | 13110401534315 |
7 | 1306066440131 |
oct | 225126370447 |
9 | 56608227012 |
10 | 20021113127 |
11 | 854443a694 |
12 | 3a6904439b |
13 | 1b70b8a902 |
14 | d7d020051 |
15 | 7c2a3ba02 |
hex | 4a959f127 |
20021113127 has 2 divisors, whose sum is σ = 20021113128. Its totient is φ = 20021113126.
The previous prime is 20021113097. The next prime is 20021113207. The reversal of 20021113127 is 72131112002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20021113127 - 210 = 20021112103 is a prime.
It is a super-5 number, since 5×200211131275 (a number of 53 digits) contains 55555 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20021113099 and 20021113108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20021103127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010556563 + 10010556564.
It is an arithmetic number, because the mean of its divisors is an integer number (10010556564).
Almost surely, 220021113127 is an apocalyptic number.
20021113127 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021113127 is an equidigital number, since it uses as much as digits as its factorization.
20021113127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 20.
Adding to 20021113127 its reverse (72131112002), we get a palindrome (92152225129).
The spelling of 20021113127 in words is "twenty billion, twenty-one million, one hundred thirteen thousand, one hundred twenty-seven".
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