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200211132001 = 350895705809
BaseRepresentation
bin1011101001110110000…
…0110110111001100001
3201010210001120022011011
42322131200312321201
511240013022211001
6231550431220521
720315263354126
oct2723540667141
9633701508134
10200211132001
11779aaa67861
1232976377741
1315b58ca335a
14999416074d
15531bc7bd51
hex2e9d836e61

200211132001 has 4 divisors (see below), whose sum is σ = 200216872900. Its totient is φ = 200205391104.

The previous prime is 200211131983. The next prime is 200211132047. The reversal of 200211132001 is 100231112002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 163720581376 + 36490550625 = 404624^2 + 191025^2 .

It is a cyclic number.

It is not a de Polignac number, because 200211132001 - 27 = 200211131873 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200211132071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2817816 + ... + 2887993.

It is an arithmetic number, because the mean of its divisors is an integer number (50054218225).

Almost surely, 2200211132001 is an apocalyptic number.

It is an amenable number.

200211132001 is a deficient number, since it is larger than the sum of its proper divisors (5740899).

200211132001 is an equidigital number, since it uses as much as digits as its factorization.

200211132001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5740898.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 200211132001 its reverse (100231112002), we get a palindrome (300442244003).

The spelling of 200211132001 in words is "two hundred billion, two hundred eleven million, one hundred thirty-two thousand, one".

Divisors: 1 35089 5705809 200211132001