Base | Representation |
---|---|
bin | 101101100001011101001101… |
… | …100001110000111110110011 |
3 | 222020220000002211221122212222 |
4 | 231201131031201300332303 |
5 | 202220230020001400201 |
6 | 1545451431152111255 |
7 | 60112532131020446 |
oct | 5541351541607663 |
9 | 866800084848788 |
10 | 200211201200051 |
11 | 58880103644978 |
12 | 1a55633223552b |
13 | 8793ab20bcc82 |
14 | 37623b95cb65d |
15 | 1822e45a9791b |
hex | b6174d870fb3 |
200211201200051 has 2 divisors, whose sum is σ = 200211201200052. Its totient is φ = 200211201200050.
The previous prime is 200211201200041. The next prime is 200211201200149. The reversal of 200211201200051 is 150002102112002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200211201200051 - 218 = 200211200937907 is a prime.
It is not a weakly prime, because it can be changed into another prime (200211201200041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105600600025 + 100105600600026.
It is an arithmetic number, because the mean of its divisors is an integer number (100105600600026).
Almost surely, 2200211201200051 is an apocalyptic number.
200211201200051 is a deficient number, since it is larger than the sum of its proper divisors (1).
200211201200051 is an equidigital number, since it uses as much as digits as its factorization.
200211201200051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 200211201200051 its reverse (150002102112002), we get a palindrome (350213303312053).
The spelling of 200211201200051 in words is "two hundred trillion, two hundred eleven billion, two hundred one million, two hundred thousand, fifty-one".
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