2002112113 has 4 divisors (see below), whose sum is σ = 2011601008. Its totient is φ = 1992623220.

The previous prime is 2002112081. The next prime is 2002112129. The reversal of 2002112113 is 3112112002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002112113 - 2⁵ = 2002112081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2002112093 and 2002112102.

It is not an unprimeable number, because it can be changed into a prime (2002112813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4744131 + ... + 4744552.

It is an arithmetic number, because the mean of its divisors is an integer number (502900252).

Almost surely, 2^2002112113 is an apocalyptic number.

It is an amenable number.

2002112113 is a deficient number, since it is larger than the sum of its proper divisors (9488895).

2002112113 is an equidigital number, since it uses as much as digits as its factorization.

2002112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9488894.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 2002112113 is about 44744.9674600396. The cubic root of 2002112113 is about 1260.3644097985.

Adding to 2002112113 its reverse (3112112002), we get a palindrome (5114224115).

It can be divided in two parts, 2002112 and 113, that added together give a square (2002225 = 1415²).

The spelling of 2002112113 in words is "two billion, two million, one hundred twelve thousand, one hundred thirteen".