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2002112199907 is a prime number
BaseRepresentation
bin11101001000100111001…
…011111011110011100011
321002101210122022201112021
4131020213023323303203
5230300311210344112
64131431352442311
7264435130623211
oct35104713736343
97071718281467
102002112199907
11702100161946
122840333a9397
13116a4c0341c1
146cc8d1d3cb1
153712d654907
hex1d2272fbce3

2002112199907 has 2 divisors, whose sum is σ = 2002112199908. Its totient is φ = 2002112199906.

The previous prime is 2002112199863. The next prime is 2002112200003. The reversal of 2002112199907 is 7099912112002.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2002112199907 is a prime.

It is a super-2 number, since 2×20021121999072 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2002115199907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001056099953 + 1001056099954.

It is an arithmetic number, because the mean of its divisors is an integer number (1001056099954).

Almost surely, 22002112199907 is an apocalyptic number.

2002112199907 is a deficient number, since it is larger than the sum of its proper divisors (1).

2002112199907 is an equidigital number, since it uses as much as digits as its factorization.

2002112199907 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40824, while the sum is 43.

The spelling of 2002112199907 in words is "two trillion, two billion, one hundred twelve million, one hundred ninety-nine thousand, nine hundred seven".