Base | Representation |
---|---|
bin | 11101001000100111001… |
… | …011111011110101000011 |
3 | 21002101210122022201122211 |
4 | 131020213023323311003 |
5 | 230300311210400003 |
6 | 4131431352442551 |
7 | 264435130623406 |
oct | 35104713736503 |
9 | 7071718281584 |
10 | 2002112200003 |
11 | 702100161a23 |
12 | 2840333a9457 |
13 | 116a4c034266 |
14 | 6cc8d1d3d3d |
15 | 3712d65496d |
hex | 1d2272fbd43 |
2002112200003 has 2 divisors, whose sum is σ = 2002112200004. Its totient is φ = 2002112200002.
The previous prime is 2002112199907. The next prime is 2002112200009. The reversal of 2002112200003 is 3000022112002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2002112200003 - 225 = 2002078645571 is a prime.
It is a super-3 number, since 3×20021122000033 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (2002112200009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001056100001 + 1001056100002.
It is an arithmetic number, because the mean of its divisors is an integer number (1001056100002).
Almost surely, 22002112200003 is an apocalyptic number.
2002112200003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002112200003 is an equidigital number, since it uses as much as digits as its factorization.
2002112200003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 2002112200003 its reverse (3000022112002), we get a palindrome (5002134312005).
The spelling of 2002112200003 in words is "two trillion, two billion, one hundred twelve million, two hundred thousand, three".
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