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200211313 = 1991006087
BaseRepresentation
bin10111110111011…
…11101101110001
3111221201210021211
423323233231301
5402223230223
631511120121
74650524311
oct1373575561
9457653254
10200211313
11a30177a5
1257073041
133262c543
141c839441
151289bd0d
hexbeefb71

200211313 has 4 divisors (see below), whose sum is σ = 201217600. Its totient is φ = 199205028.

The previous prime is 200211307. The next prime is 200211337. The reversal of 200211313 is 313112002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200211313 - 25 = 200211281 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200211293 and 200211302.

It is not an unprimeable number, because it can be changed into a prime (200211373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 502845 + ... + 503242.

It is an arithmetic number, because the mean of its divisors is an integer number (50304400).

Almost surely, 2200211313 is an apocalyptic number.

It is an amenable number.

200211313 is a deficient number, since it is larger than the sum of its proper divisors (1006287).

200211313 is a wasteful number, since it uses less digits than its factorization.

200211313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1006286.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 200211313 is about 14149.6046941249. The cubic root of 200211313 is about 585.0094361348.

Adding to 200211313 its reverse (313112002), we get a palindrome (513323315).

The spelling of 200211313 in words is "two hundred million, two hundred eleven thousand, three hundred thirteen".

Divisors: 1 199 1006087 200211313