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20021144040113 is a prime number
BaseRepresentation
bin1001000110101100010010…
…01011011011001010110001
32121220000001221201000220112
410203112021023123022301
510111011300333240423
6110325330412151105
74134323420264456
oct443261113331261
977800057630815
1020021144040113
116419a12951357
1222b4294768495
13b22ca79bba88
144d305846782d
1524abe1286a78
hex1235892db2b1

20021144040113 has 2 divisors, whose sum is σ = 20021144040114. Its totient is φ = 20021144040112.

The previous prime is 20021144040077. The next prime is 20021144040133. The reversal of 20021144040113 is 31104044112002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19758665085184 + 262478954929 = 4445072^2 + 512327^2 .

It is a cyclic number.

It is not a de Polignac number, because 20021144040113 - 226 = 20021076931249 is a prime.

It is not a weakly prime, because it can be changed into another prime (20021144040133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010572020056 + 10010572020057.

It is an arithmetic number, because the mean of its divisors is an integer number (10010572020057).

Almost surely, 220021144040113 is an apocalyptic number.

It is an amenable number.

20021144040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20021144040113 is an equidigital number, since it uses as much as digits as its factorization.

20021144040113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 20021144040113 its reverse (31104044112002), we get a palindrome (51125188152115).

The spelling of 20021144040113 in words is "twenty trillion, twenty-one billion, one hundred forty-four million, forty thousand, one hundred thirteen".