| Base | Representation |
|---|---|
| bin | 101101100001011101111101… |
| … | …110011010111100111100010 |
| 3 | 222020220002012021221220201200 |
| 4 | 231201131331303113213202 |
| 5 | 202220233144321333442 |
| 6 | 1545452043403342030 |
| 7 | 60112561164154410 |
| oct | 5541357563274742 |
| 9 | 866802167856650 |
| 10 | 200212011121122 |
| 11 | 58880489841630 |
| 12 | 1a556519521916 |
| 13 | 8793bb0b37800 |
| 14 | 3762454dba2b0 |
| 15 | 1822e91c2e34c |
| hex | b6177dcd79e2 |
200212011121122 has 576 divisors, whose sum is σ = 616134035462400. Its totient is φ = 45566265139200.
The previous prime is 200212011121099. The next prime is 200212011121139. The reversal of 200212011121122 is 221121110212002.
200212011121122 is a `hidden beast` number, since 200 + 2 + 120 + 111 + 211 + 22 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 200212011121095 and 200212011121104.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 355051254 + ... + 355614702.
It is an arithmetic number, because the mean of its divisors is an integer number (1069677144900).
Almost surely, 2200212011121122 is an apocalyptic number.
200212011121122 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 200212011121122, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (308067017731200).
200212011121122 is an abundant number, since it is smaller than the sum of its proper divisors (415922024341278).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200212011121122 is a wasteful number, since it uses less digits than its factorization.
200212011121122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 563579 (or 563563 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 18.
Adding to 200212011121122 its reverse (221121110212002), we get a palindrome (421333121333124).
The spelling of 200212011121122 in words is "two hundred trillion, two hundred twelve billion, eleven million, one hundred twenty-one thousand, one hundred twenty-two".
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