Base | Representation |
---|---|
bin | 1011101001110110010… |
… | …0001101100011001101 |
3 | 201010210010012222012120 |
4 | 2322131210031203031 |
5 | 11240013233324323 |
6 | 231550502123153 |
7 | 20315304005334 |
oct | 2723544154315 |
9 | 633703188176 |
10 | 200212011213 |
11 | 77a00508385 |
12 | 329767204b9 |
13 | 15b592205b6 |
14 | 999430cd1b |
15 | 531bda25e3 |
hex | 2e9d90d8cd |
200212011213 has 4 divisors (see below), whose sum is σ = 266949348288. Its totient is φ = 133474674140.
The previous prime is 200212011203. The next prime is 200212011247. The reversal of 200212011213 is 312110212002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 200212011213 - 213 = 200212003021 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200212011192 and 200212011201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200212011203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33368668533 + ... + 33368668538.
It is an arithmetic number, because the mean of its divisors is an integer number (66737337072).
Almost surely, 2200212011213 is an apocalyptic number.
It is an amenable number.
200212011213 is a deficient number, since it is larger than the sum of its proper divisors (66737337075).
200212011213 is an equidigital number, since it uses as much as digits as its factorization.
200212011213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66737337074.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 200212011213 its reverse (312110212002), we get a palindrome (512322223215).
The spelling of 200212011213 in words is "two hundred billion, two hundred twelve million, eleven thousand, two hundred thirteen".
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