Base | Representation |
---|---|
bin | 101101100001011101111110… |
… | …111111101000010010010111 |
3 | 222020220002020200120120112021 |
4 | 231201131332333220102113 |
5 | 202220233214431043333 |
6 | 1545452045400034011 |
7 | 60112561526116015 |
oct | 5541357677502227 |
9 | 866802220516467 |
10 | 200212031112343 |
11 | 5888049a0562a8 |
12 | 1a556524162907 |
13 | 8793bb5016c33 |
14 | 37624579018b5 |
15 | 1822e9387c82d |
hex | b6177efe8497 |
200212031112343 has 2 divisors, whose sum is σ = 200212031112344. Its totient is φ = 200212031112342.
The previous prime is 200212031112263. The next prime is 200212031112361. The reversal of 200212031112343 is 343211130212002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200212031112343 - 217 = 200212030981271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200212031112383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100106015556171 + 100106015556172.
It is an arithmetic number, because the mean of its divisors is an integer number (100106015556172).
Almost surely, 2200212031112343 is an apocalyptic number.
200212031112343 is a deficient number, since it is larger than the sum of its proper divisors (1).
200212031112343 is an equidigital number, since it uses as much as digits as its factorization.
200212031112343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 200212031112343 its reverse (343211130212002), we get a palindrome (543423161324345).
The spelling of 200212031112343 in words is "two hundred trillion, two hundred twelve billion, thirty-one million, one hundred twelve thousand, three hundred forty-three".
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