Base | Representation |
---|---|
bin | 1001000110101100011010… |
… | …00111110101111111001011 |
3 | 2121220000020120012211021101 |
4 | 10203112031013311333023 |
5 | 10111011414303212001 |
6 | 110325341134322231 |
7 | 4134325152600355 |
oct | 443261507657713 |
9 | 77800216184241 |
10 | 20021210210251 |
11 | 6419a47236a18 |
12 | 22b42b2959377 |
13 | b22cb86192c3 |
14 | 4d30631700d5 |
15 | 24abe6ea7a01 |
hex | 12358d1f5fcb |
20021210210251 has 2 divisors, whose sum is σ = 20021210210252. Its totient is φ = 20021210210250.
The previous prime is 20021210210137. The next prime is 20021210210269. The reversal of 20021210210251 is 15201201212002.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20021210210251 - 27 = 20021210210123 is a prime.
It is not a weakly prime, because it can be changed into another prime (20021210280251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010605105125 + 10010605105126.
It is an arithmetic number, because the mean of its divisors is an integer number (10010605105126).
Almost surely, 220021210210251 is an apocalyptic number.
20021210210251 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021210210251 is an equidigital number, since it uses as much as digits as its factorization.
20021210210251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 160, while the sum is 19.
Adding to 20021210210251 its reverse (15201201212002), we get a palindrome (35222411422253).
The spelling of 20021210210251 in words is "twenty trillion, twenty-one billion, two hundred ten million, two hundred ten thousand, two hundred fifty-one".
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