Base | Representation |
---|---|
bin | 1001000110101100011011… |
… | …01101001110110001110011 |
3 | 2121220000021020122202112122 |
4 | 10203112031231032301303 |
5 | 10111011424310323443 |
6 | 110325342124344455 |
7 | 4134325332110342 |
oct | 443261555166163 |
9 | 77800236582478 |
10 | 20021220011123 |
11 | 6419a51820511 |
12 | 22b42b60a512b |
13 | b22cba66b336 |
14 | 4d30645a1b59 |
15 | 24abe7c91968 |
hex | 12358db4ec73 |
20021220011123 has 2 divisors, whose sum is σ = 20021220011124. Its totient is φ = 20021220011122.
The previous prime is 20021220011113. The next prime is 20021220011129. The reversal of 20021220011123 is 32111002212002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20021220011123 - 212 = 20021220007027 is a prime.
It is a super-2 number, since 2×200212200111232 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20021220011129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010610005561 + 10010610005562.
It is an arithmetic number, because the mean of its divisors is an integer number (10010610005562).
Almost surely, 220021220011123 is an apocalyptic number.
20021220011123 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021220011123 is an equidigital number, since it uses as much as digits as its factorization.
20021220011123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 20021220011123 its reverse (32111002212002), we get a palindrome (52132222223125).
The spelling of 20021220011123 in words is "twenty trillion, twenty-one billion, two hundred twenty million, eleven thousand, one hundred twenty-three".
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