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2002122101011 = 9112197719101
BaseRepresentation
bin11101001000100111110…
…001101101000100010011
321002101211022221202021211
4131020213301231010103
5230300321224213021
64131432345000551
7264435311031334
oct35104761550423
97071738852254
102002122101011
1170210580477a
12284036783157
13116a510bca46
146cc9065028b
153712e45d3e1
hex1d227c6d113

2002122101011 has 4 divisors (see below), whose sum is σ = 2004319821024. Its totient is φ = 1999924381000.

The previous prime is 2002122101003. The next prime is 2002122101039. The reversal of 2002122101011 is 1101012212002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2002122101011 - 23 = 2002122101003 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2002122100982 and 2002122101000.

It is not an unprimeable number, because it can be changed into a prime (2002122101311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1098858640 + ... + 1098860461.

It is an arithmetic number, because the mean of its divisors is an integer number (501079955256).

Almost surely, 22002122101011 is an apocalyptic number.

2002122101011 is a deficient number, since it is larger than the sum of its proper divisors (2197720013).

2002122101011 is an equidigital number, since it uses as much as digits as its factorization.

2002122101011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2197720012.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 2002122101011 its reverse (1101012212002), we get a palindrome (3103134313013).

The spelling of 2002122101011 in words is "two trillion, two billion, one hundred twenty-two million, one hundred one thousand, eleven".

Divisors: 1 911 2197719101 2002122101011