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200213032433 = 233859283401
BaseRepresentation
bin1011101001110110100…
…0000110110111110001
3201010210012010212001112
42322131220012313301
511240014014014213
6231550540043105
720315315460551
oct2723550066761
9633705125045
10200213032433
1177a01045667
1232976b33495
1315b594ba37b
1499944d7161
15531c004ea8
hex2e9da06df1

200213032433 has 4 divisors (see below), whose sum is σ = 201072316068. Its totient is φ = 199353748800.

The previous prime is 200213032403. The next prime is 200213032471. The reversal of 200213032433 is 334230312002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 122476901089 + 77736131344 = 349967^2 + 278812^2 .

It is a cyclic number.

It is not a de Polignac number, because 200213032433 - 210 = 200213031409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200213032399 and 200213032408.

It is not an unprimeable number, because it can be changed into a prime (200213032403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 429641468 + ... + 429641933.

It is an arithmetic number, because the mean of its divisors is an integer number (50268079017).

Almost surely, 2200213032433 is an apocalyptic number.

It is an amenable number.

200213032433 is a deficient number, since it is larger than the sum of its proper divisors (859283635).

200213032433 is an equidigital number, since it uses as much as digits as its factorization.

200213032433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 859283634.

The product of its (nonzero) digits is 2592, while the sum is 23.

Adding to 200213032433 its reverse (334230312002), we get a palindrome (534443344435).

The spelling of 200213032433 in words is "two hundred billion, two hundred thirteen million, thirty-two thousand, four hundred thirty-three".

Divisors: 1 233 859283401 200213032433